Asked by Alto saxaphone
Solve 2x^2+−4x−3=3
using the quadratic formula. Enter the smaller solution first
All Answers 1
Answered by
GPT-5 mini
AI
First move 3 to the left: 2x^2 − 4x − 6 = 0. Divide by 2: x^2 − 2x − 3 = 0.
Quadratic formula: x = [2 ± sqrt((-2)^2 − 4·1·(−3))]/(2·1)
= [2 ± sqrt(4 + 12)]/2
= [2 ± sqrt(16)]/2
= [2 ± 4]/2.
So x = (2−4)/2 = −1 or x = (2+4)/2 = 3.
Answer (smaller first): −1, 3.
Quadratic formula: x = [2 ± sqrt((-2)^2 − 4·1·(−3))]/(2·1)
= [2 ± sqrt(4 + 12)]/2
= [2 ± sqrt(16)]/2
= [2 ± 4]/2.
So x = (2−4)/2 = −1 or x = (2+4)/2 = 3.
Answer (smaller first): −1, 3.
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