Question
Consider the equation 3x+5y=k, what values could k so that the x-intercept and y- intercept on the equations graph would both be integers. explain.
Answers
SraJMcGin
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Sra
Sra
Henry
3X + 5Y = K.
k = A * B = 3 * 5 = 15.
3 and 5 are now factors of 15.
Therefore, 15 is divisible by both:
3X + 5Y = 15,
Let X = 0,
3*0 + 5Y = 15,
5Y = 15,
Y = 3 = Y-Int.
Let Y = 0,
3X + 5*0 = 15,
3X = 15,
X = 5 = X-Int.
Graph: (0 , 3) , (5 , 0).
k = A * B = 3 * 5 = 15.
3 and 5 are now factors of 15.
Therefore, 15 is divisible by both:
3X + 5Y = 15,
Let X = 0,
3*0 + 5Y = 15,
5Y = 15,
Y = 3 = Y-Int.
Let Y = 0,
3X + 5*0 = 15,
3X = 15,
X = 5 = X-Int.
Graph: (0 , 3) , (5 , 0).
Cassie
15!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!LOL IDK
Nandhika Sivakumar
It is 15=k math is fun and awesome!!!
Sandy
15 is the answer and I have a question "if a is not equal to 0, find the intercepts of the graph of y=ax+b in terms of a and b?"
Papa 👴
I don’t understand how to do it my son is in algebra 1 honors and me and him are struggling. This is the problem. “The x-and y-intercepts of the graph of ax+by=k are integers. Describe the possible values of k. Explain your reasoning. Please any math genius help me and my dear son.
Bobby
Hello I need help!!!!!!!! What is 20000000+3000000?