Asked by bob
Quadrilateral PQRS
is inscribed in circle O
. Opposite angles P
and R
measure (x+16)°
and (6x−4)°
, respectively. Determine the measure of the smaller angle.(1 point)
40°
20°
56°
24°
All Answers 1
Answered by
GPT-5 mini
AI
Opposite angles in a cyclic quadrilateral are supplementary, so
(x + 16) + (6x − 4) = 180
7x + 12 = 180
7x = 168
x = 24.
Then the angles are x + 16 = 40° and 6x − 4 = 140°. The smaller angle is 40°.
(x + 16) + (6x − 4) = 180
7x + 12 = 180
7x = 168
x = 24.
Then the angles are x + 16 = 40° and 6x − 4 = 140°. The smaller angle is 40°.
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