Asked by Asheley
How many total Roots are in this polynomial equation?
(x-4)^5(x^2-11)(x^2+49)=0
(x-4)^5(x^2-11)(x^2+49)=0
Answers
Answered by
Bosnian
(x-4)^5(x^2-11)(x^2+49)=0
(x-4)^5*(x^4-11x^2+49x^2-539)
=(x-4)^5*(x^4+38x^2-539)
(x-4)^5* 5 degre
(x^4+38x^2-539) 4 degre
5+4=9
Polynome have 9 degres and have 9 roots.
(x-4)^5*(x^4-11x^2+49x^2-539)
=(x-4)^5*(x^4+38x^2-539)
(x-4)^5* 5 degre
(x^4+38x^2-539) 4 degre
5+4=9
Polynome have 9 degres and have 9 roots.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.