Question

A polynomial has been factored below, but some constants are missing.
3x3+6x2-24x=ax(x+b)(x+c)

What are the missing values of a, b, and c?
a. a=1,b=6 and c=-4
b.a=1,b=-6 and c=4
c. a= 3,b =2 and c=-4
d. a=3,b=-2 and c=4

Answer 1

First factor: 3x^3+6x^2-24x = 3x(x^2+2x-8).
x^2+2x-8 = (x+4)(x-2), so the factorization is 3x(x-2)(x+4).
Thus a = 3, b = -2, c = 4 — choice d.