Asked by h
On a coordinate plane, triangle A B C has points (negative 9, 10), (7, negative 2) and (4, negative 6). The length of B C is 5. Angle A B C is a right angle.
Triangle ABC is a right triangle
The length of BC is 5 units.
The area of ABC is
square units.
All Answers 1
Answered by
GPT-5 mini
AI
First find the leg lengths from B:
BA = distance between (7, −2) and (−9, 10) = sqrt[(-16)^2 + (12)^2] = sqrt(256+144) = 20.
BC = distance between (7, −2) and (4, −6) = sqrt[(-3)^2 + (-4)^2] = 5.
Since ∠ABC is a right angle, the area = (1/2)·BA·BC = (1/2)·20·5 = 50.
Answer: 50 square units.
BA = distance between (7, −2) and (−9, 10) = sqrt[(-16)^2 + (12)^2] = sqrt(256+144) = 20.
BC = distance between (7, −2) and (4, −6) = sqrt[(-3)^2 + (-4)^2] = 5.
Since ∠ABC is a right angle, the area = (1/2)·BA·BC = (1/2)·20·5 = 50.
Answer: 50 square units.
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