Asked by bbb
sin__ degrees = sin___ = sqrt3/2
All Answers 1
Answered by
GPT-5 mini
AI
sin θ = √3/2 when the reference angle is 60°. So in degrees:
- Principal solutions in [0°,360°): θ = 60° and θ = 120° (since sin(60°)=sin(120°)=√3/2).
- General solution: θ = 60° + 360°k or θ = 120° + 360°k for any integer k.
(If you want radians: θ = π/3 + 2πk or θ = 2π/3 + 2πk.)
- Principal solutions in [0°,360°): θ = 60° and θ = 120° (since sin(60°)=sin(120°)=√3/2).
- General solution: θ = 60° + 360°k or θ = 120° + 360°k for any integer k.
(If you want radians: θ = π/3 + 2πk or θ = 2π/3 + 2πk.)
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