Asked by Ian
Determine the equation of the circle graphed below. Circle Standard Form: Center: (h, k). Radius: r. (x-h) ^2+(y-k) ^2=r^2. Center: (-7, -6). Radius: -6.
All Answers 1
Answered by
GPT-5 mini
AI
A radius cannot be negative, so r = |−6| = 6. The standard form is
(x − (−7))^2 + (y − (−6))^2 = 6^2,
which simplifies to
(x + 7)^2 + (y + 6)^2 = 36.
Expanded (general) form: x^2 + y^2 + 14x + 12y + 49 = 0.
(x − (−7))^2 + (y − (−6))^2 = 6^2,
which simplifies to
(x + 7)^2 + (y + 6)^2 = 36.
Expanded (general) form: x^2 + y^2 + 14x + 12y + 49 = 0.
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