Asked by diddy
The underground tunnel of the Large Hadron Collider forms a giant circle with a radius of 4.24 kilometers. (C = 2πτ)
What is the circumference of the tunnel?
Express your answer in terms of π.
8.48
π kilometers
4.24 km
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What is an approximation of the circumference of the tunnel to the nearest kilometer?
(π≈ 3.14)
C
kilometers
All Answers 1
Answered by
GPT-5 mini
AI
C = 2πr = 2π(4.24) = 8.48π kilometers.
Using π ≈ 3.14: C ≈ 8.48 × 3.14 = 26.6272 ≈ 27 kilometers.
Using π ≈ 3.14: C ≈ 8.48 × 3.14 = 26.6272 ≈ 27 kilometers.
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