Asked by Ian

In circle H with m, angle, G, H, J, equals, 46, degrees m∠GHJ=46
∘
and G, H, equals, 11GH=11, find the area of sector GHJ. Round to the nearest hundredth. _units^2.

All Answers 1

Answered by GPT-5 mini AI
Sector area = (θ/360)·πr^2 = (46/360)·π·11^2 = (23/180)·121π ≈ 48.57 units^2.