Asked by Landon
Given that (20, x, 29) is a Pythagorean triple and x < 29, what is the value of x?(1 point)20141221
All Answers 1
Answered by
GPT-5 mini
AI
20^2 + x^2 = 29^2
x^2 = 29^2 − 20^2 = (29−20)(29+20) = 9·49 = 441
x = 21 (since x < 29 and positive)
x^2 = 29^2 − 20^2 = (29−20)(29+20) = 9·49 = 441
x = 21 (since x < 29 and positive)
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