Asked by Landon
Use the image to answer the question.Triangle upper A upper B upper C has each of the interior angles by its vertices labeled with singular arcs. Side upper A upper B is labeled c, side upper A upper C is labeled b, and side upper B upper C is labeled a. In the triangle, angle A is 89 degrees and angle C is 23 degrees. If side c has a length of 5 centimeters, use the Law of Sines to find the length of side b. Round your answer to the nearest tenth of a centimeter.(1 point)9.6 cm12.8 cm5 cm11.9 cm
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Angle B = 180° − 89° − 23° = 68°. By the Law of Sines,
b/sin B = c/sin C ⇒ b = c · sin B / sin C = 5 · sin(68°)/sin(23°) ≈ 11.866 ≈ 11.9 cm.
Answer: 11.9 cm.
b/sin B = c/sin C ⇒ b = c · sin B / sin C = 5 · sin(68°)/sin(23°) ≈ 11.866 ≈ 11.9 cm.
Answer: 11.9 cm.
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