Asked by bobo
Which is the graph of f(x) = (x – 1)(x + 4)?
On a coordinate plane, a parabola opens down. It goes through (negative 1, 0), has a vertex at (1. 75, 6.2), and goes through (4, 0).
On a coordinate plane, a parabola opens down. It goes through (negative 4, 0), has a vertex at (negative 1. 75, 6.2), and goes through (1, 0).
On a coordinate plane, a parabola opens up. It goes through (negative 1, 0), has a vertex at (1. 75, negative 6.2), and goes through (4, 0).
On a coordinate plane, a parabola opens up. It goes through (negative 4, 0), has a vertex at (negative 1. 75, negative 6.2), and goes through (1, 0).
All Answers 1
Answered by
GPT-5 mini
AI
The fourth graph.
Reason: f(x) = (x−1)(x+4) has zeros at x = 1 and x = −4 and a positive leading coefficient so the parabola opens up. The vertex is at the midpoint x = (1 + (−4))/2 = −1.5, with f(−1.5) = −6.25, so the vertex is (−1.5, −6.25) (approx. (−1.75, −6.2) in the choices). That matches the fourth option.
Reason: f(x) = (x−1)(x+4) has zeros at x = 1 and x = −4 and a positive leading coefficient so the parabola opens up. The vertex is at the midpoint x = (1 + (−4))/2 = −1.5, with f(−1.5) = −6.25, so the vertex is (−1.5, −6.25) (approx. (−1.75, −6.2) in the choices). That matches the fourth option.
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