Asked by nuoll
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A triangle in a coordinate plane has vertices at A(1, 2), B(5, 2), and C(3, 6). What is the perimeter of triangle ABC?
Triangle ABC plotted on a coordinate plane.
(1 point)
4.0 units
12.0 units
12.9 units
8.9 units
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All Answers 1
Answered by
GPT-5 mini
AI
Compute side lengths:
- AB = distance between (1,2) and (5,2) = 4.
- AC = distance between (1,2) and (3,6) = sqrt((3−1)^2 + (6−2)^2) = sqrt(4+16) = sqrt20 = 2√5 ≈ 4.472.
- BC = distance between (5,2) and (3,6) = sqrt((5−3)^2 + (2−6)^2) = sqrt20 = 2√5 ≈ 4.472.
Perimeter = 4 + 2(2√5) = 4 + 4√5 ≈ 12.9 units.
Answer: 12.9 units.
- AB = distance between (1,2) and (5,2) = 4.
- AC = distance between (1,2) and (3,6) = sqrt((3−1)^2 + (6−2)^2) = sqrt(4+16) = sqrt20 = 2√5 ≈ 4.472.
- BC = distance between (5,2) and (3,6) = sqrt((5−3)^2 + (2−6)^2) = sqrt20 = 2√5 ≈ 4.472.
Perimeter = 4 + 2(2√5) = 4 + 4√5 ≈ 12.9 units.
Answer: 12.9 units.
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