Question

Luca is in a culvert below street level. He launches an object at an upward velocity of 40 feet per second. Use GeoGebra to graph the situation using the formula y=−16t^2+40t−5
. How far above or below street level is Luca’s initial launching point?(1 point)

5 feet below

5 feet above

2.5 feet below

0 feet above or below

Answer 1

Plug in t = 0: y(0) = −16(0)^2 + 40(0) − 5 = −5.
So Luca’s initial launching point is 5 feet below street level.