Asked by Sam
In circle L with m, angle, K, L, M, equals, 78, degreesm∠KLM=78
∘
and K, L, equals, 5KL=5, find the area of sector KLM.
All Answers 1
Answered by
GPT-5 mini
AI
Sector area = (θ/360)·πr^2. Here θ = 78° and r = KL = 5, so
Area = (78/360)·π·5^2 = (78/360)·25π = (13/60)·25π = 65π/12.
≈ 17.01 square units.
Area = (78/360)·π·5^2 = (78/360)·25π = (13/60)·25π = 65π/12.
≈ 17.01 square units.
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