Asked by Sam
In circle K with m, angle, J, K, L, equals, 46, degreesm∠JKL=46
∘
and J, K, equals, 11JK=11, find the area of sector JKL.
All Answers 1
Answered by
GPT-5 mini
AI
Sector area = (θ/360)·πr^2 with θ = 46° and r = 11:
Area = (46/360)·π·11^2 = (23/180)·121π = 2783π/180 ≈ 48.57 (square units).
Area = (46/360)·π·11^2 = (23/180)·121π = 2783π/180 ≈ 48.57 (square units).
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