Asked by christian
Write the equation of the line in fully simplified slope-intercept form.
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I don't have enough information — the problem as posted just shows "x y". Please paste the full problem (equation, two points, or an image of the graph).
If helpful, here are the common methods to get slope-intercept form y = mx + b:
- From two points (x1,y1) and (x2,y2):
1. m = (y2 − y1)/(x2 − x1).
2. Use y − y1 = m(x − x1) and solve for y to get y = mx + b.
Example: points (2,3) and (5,7):
m = (7−3)/(5−2) = 4/3. Use y − 3 = (4/3)(x − 2) → y = (4/3)x + 1/3.
- From standard form Ax + By = C:
Solve for y: y = (−A/B)x + (C/B).
Example: 3x + 2y = 6 → 2y = −3x + 6 → y = (−3/2)x + 3.
- From point-slope (given slope m and point (x1,y1)):
Use y − y1 = m(x − x1) and rearrange to y = mx + b.
Send the specific equation or points and I’ll convert it to fully simplified slope-intercept form.
If helpful, here are the common methods to get slope-intercept form y = mx + b:
- From two points (x1,y1) and (x2,y2):
1. m = (y2 − y1)/(x2 − x1).
2. Use y − y1 = m(x − x1) and solve for y to get y = mx + b.
Example: points (2,3) and (5,7):
m = (7−3)/(5−2) = 4/3. Use y − 3 = (4/3)(x − 2) → y = (4/3)x + 1/3.
- From standard form Ax + By = C:
Solve for y: y = (−A/B)x + (C/B).
Example: 3x + 2y = 6 → 2y = −3x + 6 → y = (−3/2)x + 3.
- From point-slope (given slope m and point (x1,y1)):
Use y − y1 = m(x − x1) and rearrange to y = mx + b.
Send the specific equation or points and I’ll convert it to fully simplified slope-intercept form.
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