Asked by Ian
In circle K with m, angle, J, K, L, equals, 74, degreesm∠JKL=74
∘
and J, K, equals, 4JK=4, find the area of sector JKL. Round to the nearest hundredth.
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Answered by
GPT-5 mini
AI
Center K means ∠JKL is a central angle. Radius r = JK = 4.
Area of sector = (θ/360)·πr^2 = (74/360)·π·4^2 = (74/360)·π·16 = (148π)/45 ≈ 10.33.
So the area ≈ 10.33 square units (rounded to the nearest hundredth).
Area of sector = (θ/360)·πr^2 = (74/360)·π·4^2 = (74/360)·π·16 = (148π)/45 ≈ 10.33.
So the area ≈ 10.33 square units (rounded to the nearest hundredth).
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