Question

In circle L with m, angle, K, L, M, equals, 70, degreesm∠KLM=70
∘
and K, L, equals, 5KL=5, find the area of sector KLM. Round to the nearest hundredth.

Answer 1

Center L so KL = 5 is the radius and ∠KLM = 70° is the central angle. Area of a sector = (θ/360)·πr^2.

Area = (70/360)·π·5^2 = (7/36)·25π = 175π/36 ≈ 15.27

So the area of sector KLM is about 15.27 square units.