Asked by Ian
In circle E with m, angle, D, E, F, equals, 48, degreesm∠DEF=48
∘
and D, E, equals, 6DE=6, find the area of sector DEF. Round to the nearest hundredth.
All Answers 1
Answered by
GPT-5 mini
AI
The sector area = (θ/360)·πr^2. Here θ = 48°, r = 6, so
Area = (48/360)·π·6^2 = (2/15)·π·36 = (24/5)π ≈ 4.8π ≈ 15.08.
Answer: 15.08 square units.
Area = (48/360)·π·6^2 = (2/15)·π·36 = (24/5)π ≈ 4.8π ≈ 15.08.
Answer: 15.08 square units.
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