Question

Evaluating Substituted Values of x
x Substituted Evaluate True Statement?
−23

0
12
For the quadratic equation x2+20x=69
, complete the table by testing each of the given values to determine whether it is a solution. Identify which one of these values is in the solution set.

Answer 1

x = −23: substitute (−23)^2 + 20(−23) = 529 − 460 = 69 → True (so −23 is a solution)

x = 0: substitute 0^2 + 20·0 = 0 ≠ 69 → False (not a solution)

x = 12: substitute 12^2 + 20·12 = 144 + 240 = 384 ≠ 69 → False (not a solution)

Only −23 from the list is in the solution set. (The other root of x^2+20x=69 is x = 3, which was not listed.)