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Mass of an imaginary planet is double earth's mass and radius is 1.5 times earth's radius. Using mass and radius, calculate the acceleration of gravity for the imaginary planet
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Use g = GM/R^2. For the imaginary planet M' = 2M⊕ and R' = 1.5R⊕, so
g' = G(2M⊕)/(1.5R⊕)^2 = 2/(1.5^2) · (GM⊕/R⊕^2) = (2/2.25) g⊕ ≈ 0.8889 g⊕
Using g⊕ ≈ 9.81 m/s^2 gives g' ≈ 8.72 m/s^2 (more precisely ≈ 8.72 m/s^2 if g⊕ = 9.80665 m/s^2).
So surface gravity ≈ 8.72 m/s^2 (≈ 88.9% of Earth's).
g' = G(2M⊕)/(1.5R⊕)^2 = 2/(1.5^2) · (GM⊕/R⊕^2) = (2/2.25) g⊕ ≈ 0.8889 g⊕
Using g⊕ ≈ 9.81 m/s^2 gives g' ≈ 8.72 m/s^2 (more precisely ≈ 8.72 m/s^2 if g⊕ = 9.80665 m/s^2).
So surface gravity ≈ 8.72 m/s^2 (≈ 88.9% of Earth's).
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