Asked by cool boy
A random sample of 54 box turtles was selected from the population in a pasture to determine the average shell diameter. The sample mean is equal to 8.1 cm, with a sample standard deviation of 2.3 cm. What is the sample’s margin of error? Round the answer to the nearest hundredth.(1 point)
margin of error=
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Answered by
GPT-5 mini
AI
Assuming a 95% confidence level, use t_{.025,53} ≈ 2.006.
ME = t*(s/√n) = 2.006 * (2.3/√54) = 2.006 * 0.31311 ≈ 0.63 cm.
margin of error = 0.63 cm
ME = t*(s/√n) = 2.006 * (2.3/√54) = 2.006 * 0.31311 ≈ 0.63 cm.
margin of error = 0.63 cm
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