Asked by huhhf3;q
Which of the following expressions is equivalent to
(1 point)
csc x cos 2x - secx sin 2x
secxcos2x- csex sin 2x
secxcosx - cscx sin x
cscxcosx-secxsinx
All Answers 1
Answered by
GPT-5 mini
AI
The problem text looks garbled, so I'll simplify each of the four expressions you listed. Then you can tell me which one was supposed to be the target.
Let sinx ≠ 0 and cosx ≠ 0.
- csc x cos 2x - sec x sin 2x
= (cos2x)/sinx - (sin2x)/cosx
= (cos2x cosx - sin2x sinx)/(sinx cosx)
= cos(3x)/(sinx cosx).
- sec x cos 2x - csc x sin 2x
= (cos2x)/cosx - (sin2x)/sinx
= cos2x/cosx - 2 cosx
= (cos2x - 2cos^2 x)/cosx
= -1/cosx
= -sec x.
- sec x cos x - csc x sin x
= (1/cosx)cosx - (1/sinx)sinx
= 1 - 1
= 0.
- csc x cos x - sec x sin x
= cosx/sinx - sinx/cosx
= (cos^2 x - sin^2 x)/(sinx cosx)
= cos2x/(sinx cosx).
So:
- csc x cos 2x - sec x sin 2x = cos3x/(sinx cosx).
- None of the other three expressions simplifies to cos3x/(sinx cosx) for all x (they simplify to -sec x, 0, and cos2x/(sinx cosx), respectively).
If you tell me exactly which expression was being matched (or paste the original unformatted problem), I’ll pick the correct choice.
Let sinx ≠ 0 and cosx ≠ 0.
- csc x cos 2x - sec x sin 2x
= (cos2x)/sinx - (sin2x)/cosx
= (cos2x cosx - sin2x sinx)/(sinx cosx)
= cos(3x)/(sinx cosx).
- sec x cos 2x - csc x sin 2x
= (cos2x)/cosx - (sin2x)/sinx
= cos2x/cosx - 2 cosx
= (cos2x - 2cos^2 x)/cosx
= -1/cosx
= -sec x.
- sec x cos x - csc x sin x
= (1/cosx)cosx - (1/sinx)sinx
= 1 - 1
= 0.
- csc x cos x - sec x sin x
= cosx/sinx - sinx/cosx
= (cos^2 x - sin^2 x)/(sinx cosx)
= cos2x/(sinx cosx).
So:
- csc x cos 2x - sec x sin 2x = cos3x/(sinx cosx).
- None of the other three expressions simplifies to cos3x/(sinx cosx) for all x (they simplify to -sec x, 0, and cos2x/(sinx cosx), respectively).
If you tell me exactly which expression was being matched (or paste the original unformatted problem), I’ll pick the correct choice.
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