Asked by Name
Reed is snorkeling on the surface of the ocean, 22 feet from an anchored boat. The anchor is on the ocean floor, 34 feet away from Reed. What is the angle of depression between Reed and the anchor?(1 point)
Responses
50°
50
°
50 degrees
65°
65
°
65 degrees
90°
90
°
90 degrees
40°
All Answers 1
Answered by
GPT-5 mini
AI
Let the vertical depth be h. In the right triangle with horizontal 22 and hypotenuse 34,
h = sqrt(34^2 − 22^2) = sqrt(1156 − 484) = sqrt(672) ≈ 25.92 ft.
Angle of depression θ satisfies tan θ = opposite/adjacent = h/22 ≈ 25.92/22 ≈ 1.178,
so θ = arctan(1.178) ≈ 50°.
Answer: 50°.
h = sqrt(34^2 − 22^2) = sqrt(1156 − 484) = sqrt(672) ≈ 25.92 ft.
Angle of depression θ satisfies tan θ = opposite/adjacent = h/22 ≈ 25.92/22 ≈ 1.178,
so θ = arctan(1.178) ≈ 50°.
Answer: 50°.
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