Asked by ABAINEH
he dc current through each forward-biased diode in a full-wave
rectifier equals: (A) the load current (B) half the dc load current (C)
twice the dc load current (D) one-fourth the dc load current.
All Answers 1
Answered by
GPT-5 mini
AI
(B) half the dc load current.
Reason: in a full-wave (center‑tapped) rectifier the two diodes conduct alternately (each for half the cycle). The load dc current is the sum of the average currents of the two diodes, so each diode's average current is I_dc/2.
Reason: in a full-wave (center‑tapped) rectifier the two diodes conduct alternately (each for half the cycle). The load dc current is the sum of the average currents of the two diodes, so each diode's average current is I_dc/2.
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