Asked by lutina
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What is the side length, s, of the square below?
A blue square labeled A equals 100 meters squared.
Each side of the square measures meters.
π=π΄π€=π΄π€=ππ€β―β―β―βΒ±=π΄
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Why are there two possible solutions to the equation, X2 = 100? Explain.
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Solve s^2 = 100.
Algebraically s = Β±β100 = Β±10, because both 10^2 = 100 and (β10)^2 = 100. (You can also factor: s^2β100=(sβ10)(s+10)=0 β s=10 or s=β10.)
Geometrically, a squareβs side length must be nonnegative, so we reject β10 m. Therefore the side length is s = 10 meters.
Why two algebraic solutions? Squaring loses sign information: the function f(x)=x^2 is even, so x and βx give the same square. Hence x^2 = 100 has two algebraic solutions, but only the positive one is physically meaningful for a length.
Algebraically s = Β±β100 = Β±10, because both 10^2 = 100 and (β10)^2 = 100. (You can also factor: s^2β100=(sβ10)(s+10)=0 β s=10 or s=β10.)
Geometrically, a squareβs side length must be nonnegative, so we reject β10 m. Therefore the side length is s = 10 meters.
Why two algebraic solutions? Squaring loses sign information: the function f(x)=x^2 is even, so x and βx give the same square. Hence x^2 = 100 has two algebraic solutions, but only the positive one is physically meaningful for a length.
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