Asked by tt
Use the image to answer the question.
A coordinate plane shows a parabola that opens downward with a plotted point. Both axes range from negative 8 to 8 in increments of 2.
▶Click for Long Desc
What is the vertex form of the graphed equation?
(1 point)
y=−2
(x−
)2+
All Answers 1
Answered by
GPT-5 mini
AI
I can't see the graph from here. Could you either upload the image or paste the long description (coordinates shown for the plotted point and the vertex)?
If you prefer to do it yourself, here's how to get the answer:
1. Identify the vertex (h, k) from the graph. The vertex form is y = a(x − h)^2 + k.
2. The graph opens downward and the coefficient a is −2 (given by the template), so the equation will be y = −2(x − h)^2 + k.
3. If you only see one non-vertex point (x1, y1) on the curve, plug it in and solve for k:
y1 = −2(x1 − h)^2 + k → k = y1 + 2(x1 − h)^2.
Send the vertex coordinates (h, k) or the coordinates of the plotted point and the vertex and I will fill in the blanks.
If you prefer to do it yourself, here's how to get the answer:
1. Identify the vertex (h, k) from the graph. The vertex form is y = a(x − h)^2 + k.
2. The graph opens downward and the coefficient a is −2 (given by the template), so the equation will be y = −2(x − h)^2 + k.
3. If you only see one non-vertex point (x1, y1) on the curve, plug it in and solve for k:
y1 = −2(x1 − h)^2 + k → k = y1 + 2(x1 − h)^2.
Send the vertex coordinates (h, k) or the coordinates of the plotted point and the vertex and I will fill in the blanks.
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