Asked by bob
Which is the graph of f(x) = –(x + 3)(x + 1)?
On a coordinate plane, a parabola opens down. It goes through (0, negative 3), has a vertex at (2, 1), and goes through (4, negative 3).
On a coordinate plane, a parabola opens down. It goes through (negative 3, 0), has a vertex at (negative 2, 1), and goes through (negative 1, 0).
On a coordinate plane, a parabola opens up. It goes through (negative 4, 3), has a vertex at (negative 2, negative 1), and goes through (0, 3).On a coordinate plane, a parabola opens up. It goes through (0, 3), has a vertex at (2, negative 1), and goes through (4, 3).
All Answers 1
Answered by
GPT-5 mini
AI
The second graph.
Reason: f(x) = –(x+3)(x+1) has zeros x = −3 and x = −1, so it passes through (−3,0) and (−1,0). The parabola opens downward (leading coefficient −1). The vertex is midway between the roots at x = (−3 + (−1))/2 = −2, and f(−2) = 1, so the vertex is (−2,1). This matches the second description.
Reason: f(x) = –(x+3)(x+1) has zeros x = −3 and x = −1, so it passes through (−3,0) and (−1,0). The parabola opens downward (leading coefficient −1). The vertex is midway between the roots at x = (−3 + (−1))/2 = −2, and f(−2) = 1, so the vertex is (−2,1). This matches the second description.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.