Question

1)
A farm raises pigs and chickens. The farmer has a total of
102 animals. One day he counts the legs of all his animals
and realizes he has a total of 298 legs. How many chickens
does the farmer have?

Answer 1

Let c = number of chickens, p = number of pigs.

c + p = 102
2c + 4p = 298

From the first, c = 102 − p. Substitute:
2(102 − p) + 4p = 298
204 + 2p = 298
2p = 94 → p = 47

So c = 102 − 47 = 55.

Answer: 55 chickens.