Question

The sum of three consecutive even integers (3 even integers in a row) is 120.



Use the following setup and given equation to find your solution:

1st integer = x

2nd integer = x+2

3rd integer = x+4

Equation: x+(x+2)+(x+4)=120





Solve the equation above. What is the largest of the three integers?

(1 point)

42

38

44

38, 42, 44
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Answer 1

x + (x+2) + (x+4) = 120
3x + 6 = 120
3x = 114
x = 38

The three integers are 38, 40, 42. The largest is 42.