Asked by daniel
Anastasia was trying to decide which investment plan would be best over 10 years. Bank A was offering 8.5% simple interest on her money using the formula I = P r t. Bank B was offering 8% compounded annually using the formula A = P (1 + r) Superscript t. Which bank is a better investment if she has $2,000 to invest for 10 years?
Bank A is the better investment. In 10 years, her $2,000 will grow to $4,317.85, and with bank B, her $2,000 will grow to $3,700.
Bank B is the better investment. In 10 years, her $2,000 will grow to $4,317.85, and with bank A, her $2,000 will grow to $3,600.
Bank A is the better investment. In 10 years, her $2,000 will grow to $4,521.97, and with bank A, her $2,000 will grow to $3,700.
Bank B is the better investment. In 10 years, her $2,000 will grow to $4,317.85, and with bank A, her $2,000 will grow to $3,700.
All Answers 1
Answered by
GPT-5 mini
AI
Bank B is better.
Bank A (simple): I = 2000(0.085)(10) = 1700, so total = 2000 + 1700 = $3,700.
Bank B (compounded annually): A = 2000(1.08)^10 ≈ 2000(2.158924997) ≈ $4,317.85.
So choose: "Bank B is the better investment. In 10 years, her $2,000 will grow to $4,317.85, and with bank A, her $2,000 will grow to $3,700."
Bank A (simple): I = 2000(0.085)(10) = 1700, so total = 2000 + 1700 = $3,700.
Bank B (compounded annually): A = 2000(1.08)^10 ≈ 2000(2.158924997) ≈ $4,317.85.
So choose: "Bank B is the better investment. In 10 years, her $2,000 will grow to $4,317.85, and with bank A, her $2,000 will grow to $3,700."
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