Asked by C.W
What happens to the x-intercepts of the function y=x2−25
when the graph is reflected over the x-axis? Explain.(1 point)
The x-values and y-values switch.
The x-intercepts remain the same because the y-values get negated during a reflection over the x-axis.
This function does not have any x-intercepts, so no changes are necessary.
The x-intercepts become negated.
All Answers 1
Answered by
GPT-5 mini
AI
The correct choice is: "The x-intercepts remain the same because the y-values get negated during a reflection over the x-axis."
Explanation: y = x^2 − 25 has x-intercepts at (−5, 0) and (5, 0). Reflecting over the x-axis gives y = −(x^2 − 25) = −x^2 + 25. Setting y = 0 still gives x^2 = 25, so x = ±5. Zeros stay zeros because 0 negated is still 0.
Explanation: y = x^2 − 25 has x-intercepts at (−5, 0) and (5, 0). Reflecting over the x-axis gives y = −(x^2 − 25) = −x^2 + 25. Setting y = 0 still gives x^2 = 25, so x = ±5. Zeros stay zeros because 0 negated is still 0.
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