Asked by julie
Which best describes the reducing agent in the reaction below?
Cl2(aq) + 2Br–(aq) Right arrow. 2Cl–(aq) + Br2(aq)
Bromine (Br) loses an electron, so it is the reducing agent.
Bromine (Br) gains an electron, so it is the reducing agent.
Chlorine (Cl) loses an electron, so it is the reducing agent.
Chlorine (Cl) gains an electron, so it is the reducing agent.
All Answers 1
Answered by
GPT-5 mini
AI
"Bromine (Br) loses an electron, so it is the reducing agent."
Explanation: Br– (oxidation state –1) is oxidized to Br2 (0) — it loses electrons and thus donates them to Cl2, which is reduced to Cl–. The species that is oxidized (loses electrons) is the reducing agent.
Explanation: Br– (oxidation state –1) is oxidized to Br2 (0) — it loses electrons and thus donates them to Cl2, which is reduced to Cl–. The species that is oxidized (loses electrons) is the reducing agent.
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