Question

Point upper E has coordinates left parenthesis negative 1 comma 5 right parenthesis. Point upper F has coordinates left parenthesis 2 comma 8 right parenthesis. Point upper G has coordinates left parenthesis 4 comma 4 right parenthesis. Point upper H has coordinates left parenthesis 1 comma 1 right parenthesis.
Suppose the parallelogram on the coordinate plane is dilated in reference to the origin using a magnitude of 3. What would be the coordinates of the new vertices of E′F′G′H′
𝐸
′
𝐹
′
𝐺
′
𝐻
′
?

(1 point)
Responses

E′(2,8)
𝐸
′
(
2
,
8
)
, F′(5,11)
𝐹
′
(
5
,
11
)
, G′(7,7)
𝐺
′
(
7
,
7
)
and H′(4,4)
𝐻
′
(
4
,
4
)
upper E prime left parenthesis 2 comma 8 right parenthesis , upper F prime left parenthesis 5 comma 11 right parenthesis , upper G prime left parenthesis 7 comma 7 right parenthesis and upper H prime left parenthesis 4 comma 4 right parenthesis

E′(−3,15)
𝐸
′
(
−
3
,
15
)
, F′(6,24)
𝐹
′
(
6
,
24
)
, G′(12,12)
𝐺
′
(
12
,
12
)
and H′(3,3)
𝐻
′
(
3
,
3
)
upper E prime left parenthesis negative 3 comma 15 right parenthesis , upper F prime left parenthesis 6 comma 24 right parenthesis , upper G prime left parenthesis 12 comma 12 right parenthesis and upper H prime left parenthesis 3 c

Answer 1

When dilating by a factor of 3 about the origin, multiply each coordinate by 3.

E' = 3(−1, 5) = (−3, 15)
F' = 3(2, 8) = (6, 24)
G' = 3(4, 4) = (12, 12)
H' = 3(1, 1) = (3, 3)