Asked by yo mama
The coordinates of points upper C and upper D are as follows: upper C at left parenthesis 3 comma negative 6 right parenthesis and upper D at left parenthesis 6 comma negative 3 right parenthesis. The third unlabeled point is located at the origin. The line connecting upper C with upper D is solid. The line connecting upper C with the origin point is dotted and extends past both points. The line connecting upper D with the origin point is a hybrid solid and dotted line that extends past both points.
Which statement is part of the proof that the dilation of CD¯¯¯¯¯¯¯¯
𝐶
𝐷
¯
with a scale factor of 13
1
3
and a center of dilation at the origin will result in a line segment that is 13
1
3
the length of CD¯¯¯¯¯¯¯¯
𝐶
𝐷
¯
?
(1 point)
Responses
The length of C′D′¯¯¯¯¯¯¯¯¯¯¯
𝐶
′
𝐷
′
¯
is approximately 4.24.
The length of line segment cap c prime cap d prime is approximately 4.24.
The length of C′D′¯¯¯¯¯¯¯¯¯¯¯
𝐶
′
𝐷
′
¯
is approximately 1.41 units.
The length of line segment cap c prime cap d prime is approximately 1.41 units.
C′
𝐶
′
is at (9,−18)
(
9
,
−
18
)
and D′
𝐷
′
is at (18,−9)
(
18
,
−
9
All Answers 1
Answered by
GPT-5 mini
AI
Answer: "The length of C′D′ is approximately 1.41 units."
Reason: CD = sqrt[(6−3)^2 + (−3−(−6))^2] = sqrt(3^2+3^2) = sqrt(18) ≈ 4.2426, and (1/3)·CD ≈ 4.2426/3 ≈ 1.4142 ≈ 1.41, so C′D′ ≈ 1.41.
Reason: CD = sqrt[(6−3)^2 + (−3−(−6))^2] = sqrt(3^2+3^2) = sqrt(18) ≈ 4.2426, and (1/3)·CD ≈ 4.2426/3 ≈ 1.4142 ≈ 1.41, so C′D′ ≈ 1.41.
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