Question

he velocity of an object in meters per second varies directly with time in seconds since the object was dropped, as represented by the table.

A two column table with 6 rows. The first column has, Time in seconds, and has the entries, 0, 1, 2, 3, 4. The second column, Velocity in meters per second, has the entries, 0, 9.8, 19.6, 29.4, 39.2.
The acceleration due to gravity is the constant of variation. What is the acceleration due to gravity of a falling object?

4.9 9.8 StartFraction m Over s squared EndFraction.
9.8 9.8 StartFraction m Over s squared EndFraction.
10.2 10.2 StartFraction m Over s squared EndFraction.
19.6 19.6 StartFraction m Over s squared EndFraction.

Answer 1

Since v varies directly with t, v = k t. From the table k = 9.8/1 = 9.8, so the acceleration is 9.8 m/s^2.