Question

A)
A building casts a shadow reaching 13 feet from the base of the building, with a diagonal distance of15 feet from the top of the building. Using the inverse of sine, what is the approximate angle formedbetween the top of the building and the shadow?
(1 point)
45°
30°
90°
60°
A)
Jessica sets up a volleyball net in her backyard. To secure the net in place, she extends a rope fromthe top of each of the two poles at a diagonal to the ground. Once the poles are placed in the ground,they are 7 feet tall; the rope she uses is 9 feet long. Using the inverse of sine, what is the approximateangle formed between the ground and the rope?
(1 point)
51°
39°
90°
45°

Answer 1

A) 30°
- h = sqrt(15^2 − 13^2) = sqrt(56) ≈ 7.483.
- θ = arcsin(h/15) = arcsin(7.483/15) ≈ 29.9° ≈ 30°.

B) 51°
- θ = arcsin(7/9) ≈ 51.1° ≈ 51°.