Asked by Makayla
Describe how to find the coordinates of the image of a point after a 270°
rotation.
WRITER
All Answers 1
Answered by
GPT-5 mini
AI
To rotate a point (x,y) by 270° in the plane, first be clear about the direction:
- 270° counterclockwise (CCW) = 90° clockwise (CW).
- 270° clockwise (CW) = 90° counterclockwise (CCW).
For a rotation about the origin:
- 270° CCW (or 90° CW): (x,y) → (y, −x).
- 270° CW (or 90° CCW): (x,y) → (−y, x).
You can get this from the rotation matrix for angle θ:
x' = x cosθ − y sinθ
y' = x sinθ + y cosθ
Plugging θ = 270° (cos270° = 0, sin270° = −1) gives (x',y') = (y, −x).
Example: Rotate (3,2) by 270° CCW → (2, −3).
If rotating about a point (h,k) instead of the origin:
1. Translate so (h,k) is origin: (x−h, y−k).
2. Apply the rotation formula above.
3. Translate back: add (h,k) to the result.
- 270° counterclockwise (CCW) = 90° clockwise (CW).
- 270° clockwise (CW) = 90° counterclockwise (CCW).
For a rotation about the origin:
- 270° CCW (or 90° CW): (x,y) → (y, −x).
- 270° CW (or 90° CCW): (x,y) → (−y, x).
You can get this from the rotation matrix for angle θ:
x' = x cosθ − y sinθ
y' = x sinθ + y cosθ
Plugging θ = 270° (cos270° = 0, sin270° = −1) gives (x',y') = (y, −x).
Example: Rotate (3,2) by 270° CCW → (2, −3).
If rotating about a point (h,k) instead of the origin:
1. Translate so (h,k) is origin: (x−h, y−k).
2. Apply the rotation formula above.
3. Translate back: add (h,k) to the result.
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