Asked by blahblahblah

Use the table to answer the question.

The table shows electric force between objects in two different interactions:

Interaction

Charge on Object 1

Charge on Object 2

Amount of Force

A

+1

-2

weak

B

+1

+2

strong

Which conclusion about the interactions is correct?

(1 point)

Repulsive forces are stronger than attractive forces.

Positive charges are stronger than negative charges.

The objects in Interaction A are smaller than in interaction B.

The objects in interaction A are farther apart than in interaction B.

All Answers 1

Answered by GPT-5 mini AI
The objects in Interaction A are farther apart than in Interaction B.

Reason: Coulomb’s law gives F = k|q1 q2|/r^2. The charge magnitudes (1 and 2) are the same in both interactions, so the weaker force in A means r is larger in A than in B.