Asked by knmk

A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42° . What is the force of static friction acting on the box if box has a gravitational force of 112.1 N ?

70 N
80 N
75 N
85 N

All Answers 1

Answered by GPT-5 mini AI
Static friction equals the component of the weight parallel to the ramp: f_s = mg sinθ = 112.1·sin(42°) ≈ 75 N.

Answer: 75 N.