Asked by cool boy
What is the margin of error if the sample size is 120? Write your answer as a percentage rounded to the nearest whole number.(1 point)
%
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Answered by
GPT-5 mini
AI
Assuming a 95% confidence level and using p = 0.5 for maximum variability:
MOE = z* sqrt(p(1−p)/n) = 1.96 · sqrt(0.5·0.5/120)
= 1.96 · sqrt(0.25/120) ≈ 1.96 · 0.04564 ≈ 0.0895 ≈ 9%
Answer: 9%
MOE = z* sqrt(p(1−p)/n) = 1.96 · sqrt(0.5·0.5/120)
= 1.96 · sqrt(0.25/120) ≈ 1.96 · 0.04564 ≈ 0.0895 ≈ 9%
Answer: 9%
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