Question

Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)
Responses

92+16x=104+13x
; x=4

92 plus 16 x equals 104 plus 13 x ; x equals 4

104+16x=92+13x
; x=4

104 plus 16 x equals 92 plus 13 x ; x equals 4

92+16x=104+13x
; x=6

92 plus 16 x equals 104 plus 13 x ; x equals 6

92−16x=104−13x
; x=−4

Answer 1

Set 92 + 16x = 104 + 13x (x in minutes).
92 + 16x = 104 + 13x → 3x = 12 → x = 4 minutes.

After 4 minutes each has 92 + 16(4) = 156 cans (and 104 + 13(4) = 156).