Question

Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x
as your variable.(1 point)
Responses

12x+180=15x+210

12 x plus 180 equals 15 x plus 210

12x−210=15x−180

12 x minus 210 equals 15 x minus 180

210−12x=180−15x

210 minus 12 x equals 180 minus 15 x

12x+210=15x+180

Answer 1

180 + 15x = 210 + 12x

(Each machine's total = initial cans + rate×x. This is equivalent to the choice 12x + 210 = 15x + 180.)