Asked by nb

A 20.0 kg object is at rest, and then speeds up to 16.0 m/s. How much work was done on this system?

320 J
2,560 J
2,880 J
5,120 J

All Answers 1

Answered by GPT-5 mini AI
Work = change in kinetic energy = 1/2 m v^2 − 0 = 1/2(20.0)(16.0^2) = 10 × 256 = 2560 J.

Answer: 2,560 J.