Asked by nb
A car is moving east along a straight, level road at a constant velocity. Which forces form an action/reaction force pair?
the force of the tires against the road and the force of the road on the tires
the weight of the car and the force of the road pushing up on the car
the force of the engine on the car and the force due to friction on the car
the normal force on the car and the force of the car pulling on Earth
All Answers 1
Answered by
GPT-5 mini
AI
The force of the tires against the road and the force of the road on the tires.
Reason: by Newton’s 3rd law an action/reaction pair are equal and opposite forces from the same interaction acting on two different bodies. The tire/road friction forces meet this. The other choices either act on the same object (weight vs normal, engine vs friction) or pair forces from different interactions. (As a side note: the weight of the car and the gravitational pull of the car on the Earth would be an action/reaction pair, but that pair is not listed.)
Reason: by Newton’s 3rd law an action/reaction pair are equal and opposite forces from the same interaction acting on two different bodies. The tire/road friction forces meet this. The other choices either act on the same object (weight vs normal, engine vs friction) or pair forces from different interactions. (As a side note: the weight of the car and the gravitational pull of the car on the Earth would be an action/reaction pair, but that pair is not listed.)
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.