Asked by Anonymous
If y varies inversely as the square of x, and y=0.5 when x=1, find y when x=9
Answers
Answered by
Reiny
"If y varies inversely as the square of x" ---- >
y = k(1/x^2) , where k is a constant
when x=1, y = .5
sub that in to find k,
write the equation again now that you know k
sub in x=9 and you are done
y = k(1/x^2) , where k is a constant
when x=1, y = .5
sub that in to find k,
write the equation again now that you know k
sub in x=9 and you are done
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