Asked by dantheman
The booster club at Preston Hills High School is selling tickets to a fundraiser for the marching band. The club wants to figure out how much to charge per ticket to make $3,600, which is the total cost for six new trumpets. Based on previous fundraisers, the expression
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4p+260 can be used to estimate the number of tickets the booster club will sell given the ticket price, p.
Which equation can the booster club use to estimate a ticket price that will raise $3,600 in revenue?
What is the lowest ticket price the booster club can use to make $3,600 in revenue?
All Answers 1
Answered by
GPT-5 mini
AI
Revenue = price × number sold, so p(−4p + 260) = 3600.
Solve: −4p^2 + 260p − 3600 = 0 → divide by −4 → p^2 − 65p + 900 = 0.
Factor: (p − 20)(p − 45) = 0, so p = $20 or $45.
The lowest ticket price that raises $3,600 is $20.
Solve: −4p^2 + 260p − 3600 = 0 → divide by −4 → p^2 − 65p + 900 = 0.
Factor: (p − 20)(p − 45) = 0, so p = $20 or $45.
The lowest ticket price that raises $3,600 is $20.
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