Question

Calculate and compare the surface area of sphere A
𝐴
, which has a radius of 6 in., and sphere B
𝐵
, which has a radius of 24 in. The formula for the surface area of a sphere is 4πr2
4
𝜋
𝑟
2
.(1 point)
Responses

Sphere A
𝐴
has a surface area of 36π in.2
36
𝜋

in.
2
and sphere B
𝐵
has a surface area of 576π in.2
576
𝜋

in.
2
. This means that sphere B
𝐵
’s surface area is 16 times as large as sphere A
𝐴
’s.
Sphere upper A has a surface area of 36 pi in. squared and sphere upper B has a surface area of 576 pi in. squared . This means that sphere upper B ’s surface area is 16 times as large as sphere upper A ’s.

Sphere A
𝐴
has a surface area of 24π in.2
24
𝜋

in.
2
and sphere B
𝐵
has a surface area of 96π in.2
96
𝜋

in.
2
. This means that sphere B
𝐵
’s surface area is 4 times as large as sphere A
𝐴
’s.
Sphere A
𝐴
has a surface area of 6π in.2
6
𝜋

in.
2
and sphere B
𝐵
has a surface area of 24π in.2
24
𝜋

in.
2
. This means that sphere B
𝐵
’s surface area is 4 times as large as sphere A
𝐴
’s.
Sphere upper A has a surface area of 6 pi in. squared and sphere upper B has a surface area of 24 pi in. squared . This means that sphere upper B ’s surface area is 4 times as large as sphere upper A ’s.

Sphere A
𝐴
has a surface area of 144π in.2
144
𝜋

in.
2
and sphere B
𝐵
has a surface area of 2,304π in.2
2
,
304
𝜋

in.
2
. This means that sphere B
𝐵
’s surface area is 16 times as large as sphere A
𝐴
’s.

Answer 1

Surface area = 4πr^2.

Sphere A (r = 6): 4π(6^2) = 4π(36) = 144π in^2.
Sphere B (r = 24): 4π(24^2) = 4π(576) = 2304π in^2.

Ratio B/A = 2304π / 144π = 16, so sphere B’s surface area is 16 times sphere A’s.

(The correct option is the one giving 144π in^2 for A, 2304π in^2 for B, and that B is 16× A.)